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Nuts Questions   Message List  
Reply | Forward Message #48074 of 57779 |
Nuts Questions

I have played a few games and have read the FAQ over, but I am still
confused about In Sight Checks, Woods and Reaction.

1. If moving a group and I indicate that I want them to move
simultaneously and the moving group comes into sight of one enemy
model, does that model make a single in sight check against the group
and if it passes pick one of them to fire against, or does it make an
in sight check against each model in the group. If the latter, can it
fire at each of the members of the group that it passed against or
does it have to select one of the ones it passed against to shoot?

2. If a group begins the game in a wooded area, they are hidden. If
they move through the woods to the edge of the woods, they remain
hidden until they fire, correct?

3. If a group begins the game behind a wooded area but not in it and
the woods are between them and the enemy, are they hidden? Would they
become unhidden if any enemy model approached them and had LOS on the
from a direction that was not obstructed by the woods?

4. Can a hidden model in a wooded area (but not on the edge) see enemy
models outside the woods?

5. The rules for woods state that you can only see 12" within the
woods. Is that just for one model in the woods to see another model
also in the woods? Can a model outside the woods see a model that is
6" into the woods or can the model outside only see models on the edge?

6. Please tell me if this is correct: An active model (John) moves
into sight of an enemy model (Johannes). Johannes makes his In Sight
test and passes. He takes a shot at John and misses. John makes
received fire test and Passes 2d6. He shoots back at Johannes and
also misses. Johannes makes a received fire test and passes 2d6. He
fires back again, missing. Then John tests, passes, shoots and
successfully OOAs Johannes. Then John continues his movement and
fires one last time at a different enemy (Tomas) whom he could see and
could see him throughout his movement taking him OOA. His action is over.

Maury

PS. As an aside, the updated (Dec 2008) FAQ still has a lot of
examples in it that use the old In Sight rules (where both active and
inactive side took the test) making it very confusing (at least for
me). Perhaps it could be updated to remove or clarify the examples.




Wed Jan 14, 2009 12:00 am

howling_fang
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Message #48074 of 57779 |
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Hi, I've had this situation come up a couple times and have wondered which way is the intended way to play it. 2 Americans A and B both rep 4 move down street....
aarmada01
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Jun 21, 2006
11:22 pm

... Correct. Ed...
az_sunsets73
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Jun 21, 2006
11:48 pm

I have played a few games and have read the FAQ over, but I am still confused about In Sight Checks, Woods and Reaction. 1. If moving a group and I indicate...
howling_fang
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Jan 14, 2009
1:44 am

Here goes! ... group and if it passes pick one of them to fire against, or does it make an in sight check against each model in the group. If the latter, can...
az_sunsets73
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Jan 14, 2009
1:54 am

Hi there howling_fang, and welcome aboard! I've dragged myself away from the live Obama coverage (yep, even in little ol' New Zealand we've had live coverage...
Colin MacMillan
ColinMacMillan
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Jan 21, 2009
1:43 am

In regards to the "number of shots a weapon allows" simply consider with common sense your weapon. Assume that an activation does not allow reloading within...
Jason Lieuallen
sgtlieu
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Jan 21, 2009
2:38 am

... with common sense your weapon. Assume that an activation does not allow ... only six shots, whether active shooting or reactive shooting). Generally...
twohourwargames
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Jan 21, 2009
3:51 am

... The concept of "number of shots a weapon allows" for Reaction Shooting might be explained like this: I can go and shoot my bow and arrows 15 times during...
John Paul
paulnutsplayer
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Jan 22, 2009
7:52 am

... Shooting might be ... during my Activation ... shot of the bow. Not quite. You can fire once when active and once in reaction. Same for a musket. A weapon...
az_sunsets73
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Jan 22, 2009
5:50 pm
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