Hello everyone, First of all I would like to be another person to congratulate Noel on solving Magic120Cell! It must have taken a lot of patience and...
I have a particularly fun announcement to make tonight which is that I have finally solved the 4D cube. It might surprise many of you that I had never before...
... Congratulations! Of course, whether you had ever solved it or not, we are all forever in debt for your significant role in making this possible. :-) --Jay...
Wonderful news Melinda. Many congratulations, and I trust you will enjoy your bragging rights to the full :) Also, to echo Jay, thank-you for everything you...
Hi everyone, In yet another attempt to redefine the spirit of taking things too far, I have found the formula for the number of reachable configurations of an...
Well, it was a lengthy journey, but after 24 days (avg 6 hrs/day) and 1.9 million twists, the 7^5 is the only peak left unclaimed. After scaling the 6^5, I'm...
Congratulations!! 1.9 million twists - incredible! Also, great to hear about your solution to the m^n puzzle; I'm definitely interested in hearing more about...
I think the lack of experienced parity problems is likely due to the solution method (corners-in instead of centers-out). In Noel's writeup about higher...
... that ... occasionally ... even on a ... I would agree that a corners in approach avoids parity problems. It's the solution that I use when I solve my 4^3....
I was hoping mentioning parity would get a discussion started on this, as parity was my biggest hang-up on announcing my m^n solution. A traditional definition...
Thanks for your definition of parity and detailed explanation! Everything you said was right on. Based on your permutation-based definition of parity, I ...
First my congratulation goes to Melinda! It's great finally see you in Hall of Fame! I was really surprise how fast someone will join Noel in Hall of Insanity...
Hi guys, Thank you Levi. This deepened my understanding, especially the discussion of what you termed "double odd", as well as the "why" of single corner...
Let me be the latest person to congratulate you on your stupendous new accomplishment! Long ago I predicted that it would be a very long time, if ever, until...
Roice, you bring up a very good point. I wasn't sure there were positions on a 4^d that, using a reduction method, would generate impossible positions on a 3^d...
Thanks Melinda! I consider your congrats and a shout-out on the MC4D main page an honor. To you and anyone else in the hall of fame, you're 1 out of 100^4! ...
I dug up old cd backups I had and found my log files from April 2000! I save solutions along the way out of paranoia, and luckily I had files at the problem...
Sorry, just reread this after going to lunch with a friend and saw a couple things I wanted to clarify/correct. - The reason for the different move counts in...
Thanks, Roice. Impressive you found CD's from 2000! I'll take a look at these, and see what I think. (Actually, I'm loading them right now...) I've also...
I was looking at another site. This gives a similar insight to my position on parity, and the whole even/odd issue. http://www.ryanheise.com/cube/parity.html ...
A little more roice spam, this time inline :) (and a little of it from the earlier post). ... essentially as odd parity (and in my n^d solution double odd as ...
... For what it's worth, I agree that it's time to do that. ... I haven't played with the puzzle for far too long. Maybe it's time to give it another...
Ok, one last reply today. I'm going to trim this down to the points ... I agree completely. ... Are you refering to two corners that aren't oriented correctly?...
One last trimmed down reply for me as well :) ... not I'm not sure what you mean. On a 3^3, you cannot swap a single ... pair of corners, regardless of...
Hi guys, What a great discussion! I thought I would add my observations, based on my work with the m^n formulas. I think an important fact to realize, which...
David, thank you for the excellent email response on the parity discussion with Levi (and for the fix of my incorrect 4-cycle claim about corners on MC5D). It...
That's a delightful finding. If n=2d, then stickers=cubies. I've always thought the 6^3 had a sort of hidden beauty to it. As for the m^n or n^d. My preference...
You're welcome, Roice! I'm glad my observations helped, and great to hear you are off to solve another problem. As for your observation, check another unique...
... As I see it, the phenomenon here is just a quantized scale effect. The cubies with any stickers at all (without regard to how many stickers) are all on...
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